甲乙两人分别在A、B两地同时相向而行,与E处相遇,甲继续向B地行走,乙则休息了14分钟,再继续向A地行走,甲和乙分别到达B和A后立即折返,仍在E处相遇。已知甲每分钟走60米,乙每分钟走80米,则A和B两地相距多少米?+Y0g2v.r+M;X4C'u7l
解:
算式:提示'B:~0H7R/c4K7p)Z6v7O/h+Y0g2v.r+M;X4C'u7l
答:A和B两地相距'}9y.W1k(g4l2v*t*h3R米。+Y0g2v.r+M;X4C'u7l