一个三角形的底角是45°，顶角是底角的2倍，它的顶角是多少度？-X.A9N,[0g3p7r'H7F,t3H2p
算式：提示.h8w.P/U(b*w-X.A9N,[0g3p7r'H7F,t3H2p
答：它的顶角是(t*P+`:R9Z/M0^+Z+Z6l)[。-X.A9N,[0g3p7r'H7F,t3H2p